1962 AHSME Problems/Problem 6
Problem
A square and an equilateral triangle have equal perimeters. The area of the triangle is square inches. Expressed in inches the diagonal of the square is:
Solution
To solve for the perimeter of the triangle we plug in the formula for the area of an equilateral triangle which is (x^2*)/4. This has to be equal to so solving for x brings the answer to a side length to 6. Knowing this gives us a perimeter of 18 so each side length of the square is 4.5. Now we solve for the diagonal getting the answer of .
See Also
1962 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
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