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• 1995 AHSME Problems/Problem 11
  ==Problem== <math> \mathrm{(A) \ 10 } \qquad \mathrm{(B) \ 18 } \qquad \mathrm{(C) \ 24 } \qquad \mathrm{(D) \ 36 } \qquad \mathrm{(E) \
  2 KB (233 words) - 10:37, 30 March 2023
• 1997 PMWC Problems
  == Problem I1 == [[1997 PMWC Problems/Problem I1|Solution]]
  15 KB (2,057 words) - 19:13, 10 March 2015
• 1997 PMWC Problems/Problem I13
  == Problem == ...ath>70 \text{ km/h}</math>. It traveled <math>3</math> rounds within <math>18</math> hours. What is the distance between <math>A</math> and <math>B</math
  857 bytes (149 words) - 13:13, 21 January 2019
• 1951 AHSME Problems
  == Problem 1 == [[1951 AHSME Problems/Problem 1|Solution]]
  23 KB (3,641 words) - 22:23, 3 November 2023
• 1951 AHSME Problems/Problem 2
  == Problem == ...})\ 2x^2 \qquad (\mathrm{C})\ \frac{2x^2}9 \qquad (\mathrm{D})\ \frac{x^2}{18} \qquad (\mathrm{E})\ \frac{x^2}{72}</math>
  743 bytes (121 words) - 12:19, 5 July 2013
• Algebraic manipulation
  x^2 + 18 &= 43 \\ ...e right side to maintain equality. The right hand side becomes <math>43 - 18 = 25</math>.
  4 KB (562 words) - 18:49, 8 November 2020
• 1959 AHSME
  ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[1959 AHSME Problems/Problem 1|Problem 1]]
  3 KB (257 words) - 14:19, 20 February 2020
• 1959 AHSME Problems
  == Problem 1== [[1959 AHSME Problems/Problem 1|Solution]]
  22 KB (3,345 words) - 20:12, 15 February 2023
• 1966 AHSME Problems
  == Problem 1 == <math>\text{(A)} \ \frac 18 \qquad \text{(B)} \ \frac 73 \qquad \text{(C)} \ \frac78 \qquad \text{(D)}
  19 KB (3,159 words) - 22:10, 11 March 2024
• 1966 AHSME
  ...contains the full set of test problems. The rest contain each individual problem and its solution. ** [[1966 AHSME Problems/Problem 1|Problem 1]]
  2 KB (217 words) - 14:15, 20 February 2020
• 1966 AHSME Problems/Problem 1
  == Problem == <math>\text{(A)} \ \frac 18 \qquad \text{(B)} \ \frac 73 \qquad \text{(C)} \ \frac78 \qquad \text{(D)}
  712 bytes (99 words) - 12:39, 5 July 2013
• 2002 AMC 12B Problems/Problem 19
  == Problem == {{AMC12 box|year=2002|ab=B|num-b=18|num-a=20}}
  852 bytes (119 words) - 10:22, 4 July 2013
• 2002 AMC 12B Problems/Problem 14
  ...12B Problems|2002 AMC 12B #14]] and [[2002 AMC 10B Problems|2002 AMC 10B #18]]}} == Problem ==
  2 KB (282 words) - 14:04, 12 July 2021
• 2002 AMC 12B Problems/Problem 18
  == Problem == [[Image:2002_12B_AMC-18.png]]
  3 KB (376 words) - 19:16, 20 August 2019
• 2002 AMC 12B Problems/Problem 13
  == Problem == The sum of <math>18</math> consecutive positive integers is a [[perfect square]]. The smallest
  2 KB (261 words) - 23:34, 18 March 2023
• 2002 AMC 12B Problems/Problem 12
  == Problem == ...thrm{(D)}\ 4}</math> solutions (respectively yielding <math>n = 0, 10, 16, 18</math>).
  4 KB (579 words) - 05:54, 17 October 2023
• 2007 AMC 8 Problems
  ==Problem 1== [[2007 AMC 8 Problems/Problem 1|Solution]]
  12 KB (1,800 words) - 20:01, 8 May 2023
• 2003 AMC 12B Problems/Problem 17
  == Problem == We rewrite the logarithms in the problem. <cmath>\log(x) + 3\log(y) = 1</cmath> <cmath>2\log(x) + \log(y) = 1</cmath
  2 KB (329 words) - 13:49, 4 April 2024
• 2003 AMC 12B Problems/Problem 1
  ==Problem== <cmath>\frac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}?</cmath>
  970 bytes (134 words) - 00:09, 14 September 2015
• 2004 AMC 10A Problems/Problem 19
  ==Problem== {{AMC10 box|year=2004|ab=A|num-b=18|num-a=20}}
  2 KB (220 words) - 14:19, 21 April 2021

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