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• 2022 AIME I Problems
  ...sum is taken over the pairs of subsets <cmath>(A,B) \in \left\{(\emptyset,\emptyset),(\{1\},\{1\}),(\{1\},\{2\}),(\{2\},\{1\}),(\{2\},\{2\}),(\{1,2\},\{1,2\})\
  9 KB (1,520 words) - 19:06, 2 January 2023
• 2023 AIME II Problems/Problem 11
  ...<math>X</math> and <math>Y</math> in the collection, <math>X \cap Y \not= \emptyset.</math> This entails <math>\emptyset \in \mathcal C</math>.
  12 KB (2,014 words) - 00:58, 12 February 2024
• 2023 AMC 10B Problems/Problem 16
  ...<math>(1, 2, 3, 4, 5, 6, 7, 8, 9)</math>, excluding the empty set (<math>\emptyset</math>) and the one-digit integers. So, the number of upno integers is <mat
  8 KB (1,195 words) - 12:03, 26 February 2024
• 2024 AIME I Problems/Problem 3
  <math>\text{heap}(0) = \{\} = *\text{mex}(\emptyset) = 0</math>
  10 KB (1,628 words) - 18:50, 7 February 2024
• 2024 AIME II Problems/Problem 14
  We can easily see that all ordered partitions (except <math>A = \emptyset</math>) guarantee feasible solutions of <math>z</math>.
  4 KB (682 words) - 17:07, 2 May 2024
• 2023 CMO Problems/Problem 3
  ...emainder). It is easy to verify <math>B \cap A_{1+\left[\log _2 p\right]}=\emptyset</math>. Obviously, <math>B</math> is also a good set, so <math>\Omega-</mat
  13 KB (2,406 words) - 05:36, 25 May 2024
• 2023 CMO(CHINA) Problems/Problem 3
  ...emainder). It is easy to verify <math>B \cap A_{1+\left[\log _2 p\right]}=\emptyset</math>. Obviously, <math>B</math> is also a good set, so <math>\Omega-</mat
  13 KB (2,411 words) - 16:39, 4 June 2024

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