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- ...<math>(1, 2, 3, 4, 5, 6, 7, 8, 9)</math>, excluding the empty set (<math>\emptyset</math>) and the one-digit integers. So, the number of upno integers is <mat8 KB (1,196 words) - 07:28, 7 July 2024
- <math>\text{heap}(0) = \{\} = *\text{mex}(\emptyset) = 0</math>10 KB (1,599 words) - 14:16, 14 September 2024
- We can easily see that all ordered partitions (except <math>A = \emptyset</math>) guarantee feasible solutions of <math>z</math>.4 KB (686 words) - 13:20, 3 September 2024
- ...emainder). It is easy to verify <math>B \cap A_{1+\left[\log _2 p\right]}=\emptyset</math>. Obviously, <math>B</math> is also a good set, so <math>\Omega-</mat13 KB (2,406 words) - 05:36, 25 May 2024
- ...emainder). It is easy to verify <math>B \cap A_{1+\left[\log _2 p\right]}=\emptyset</math>. Obviously, <math>B</math> is also a good set, so <math>\Omega-</mat13 KB (2,411 words) - 16:39, 4 June 2024
- ...\cap B| = |B \cap C| = |C \cap A| = 1</math> and <math>A \cap B \cap C = \emptyset</math>. For example, <math>(\{1,2\},\{2,3\},\{1,3,4\})</math> is a minimall18 KB (3,089 words) - 11:53, 27 August 2024