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- <cmath>\frac {SL}{LC} = \frac{KB + CB} {CK}= \frac{3+5} {2} = 4. \frac{GO}{OH} = \frac{CK}{CD} = \frac{2}{5}.</cmath> <cmath>AB = 5 \implies OH = \frac {5 \sqrt{3}}{2} \implies GO = \sqrt{3}.</cmath>32 KB (5,375 words) - 11:43, 5 May 2024
- ...e at the bottom of the second peg, or the largest peg will have nowhere to go. In order for the largest ring to be at the bottom, we must first move the43 KB (7,006 words) - 14:24, 19 February 2024
- Square both sides and go through some algebraic manipulations to arrive at13 KB (2,178 words) - 11:34, 14 May 2024
- <cmath>DO = EO = GO \implies \angle DEG = 90^\circ.</cmath>29 KB (4,997 words) - 18:06, 16 May 2024
- ...ked those iTest problems, solving question after question, almost made him go insane sitting there that day. He never felt the same way when she worked o ...want the answer, and be so impressed with Joe’s brilliance that she’d go out with him on Friday night.25 KB (3,738 words) - 10:53, 23 April 2024