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• 2008 AMC 12A Problems/Problem 20
  label("\(\frac{15}{7}\)",(A+D)/2,NE); The semiperimeters are <math>s_A = \left(3 + \frac{15}{7} + \frac{12\sqrt{2}}{7}\right)\left/\right.2 = \frac{18+6\sqrt{2}}{7}</m
  6 KB (951 words) - 16:31, 2 August 2019
• 2008 AMC 12A Problems/Problem 15
  {{duplicate|[[2008 AMC 12A Problems|2008 AMC 12A #15]] and [[2008 AMC 10A Problems/Problem 24|2008 AMC 10A #24]]}}
  4 KB (547 words) - 04:19, 30 September 2023
• 2008 AMC 12A Problems/Problem 22
  label("\(B\)",(-3.15,1.35),E); label("\(D\)",(-0.75,4.15),E);
  10 KB (1,518 words) - 17:00, 16 May 2023
• 2008 AMC 12A Problems/Problem 14
  {{AMC12 box|year=2008|num-b=13|num-a=15|ab=A}}
  902 bytes (125 words) - 10:28, 13 March 2016
• 2008 AMC 12A Problems/Problem 9
  {{AMC10 box|year=2008|ab=A|num-b=13|num-a=15}}
  2 KB (256 words) - 00:31, 19 October 2020
• 2007 AMC 12B Problems/Problem 14
  {{AMC12 box|year=2007|ab=B|num-b=13|num-a=15}}
  3 KB (401 words) - 22:58, 8 May 2023
• 2007 AMC 12B Problems/Problem 23
  <math>(13, 84), (14, 48), (15, 36), (16, 30), (18, 24), (20, 21).</math> ...<math>(7, 78), (8,42), (9, 30), (10, 24), (12, 18),</math> and <math>(14, 15) \Rightarrow \mathrm{(A)}</math>.
  4 KB (725 words) - 19:59, 4 January 2024
• 2007 AMC 12B Problems/Problem 16
  <math>\mathrm{(A)}\ 15 \qquad \mathrm{(B)}\ 18 \qquad \mathrm{(C)}\ 27 \qquad \mathrm{(D)}\ 54 \qq The total is <math>3 + 6 + 3 + 3 = 15</math> appearances <math>\Rightarrow \mathrm{(A)}</math>
  3 KB (463 words) - 16:35, 15 February 2021
• 2008 AMC 10B Problems
  15&16&17&18\\\hline .... League rules state that a player must be paid at least <math>\textdollar 15,000</math> and that the total of all players' salaries for each team cannot
  12 KB (1,838 words) - 16:52, 7 October 2022
• 2008 AMC 12B Problems
  15&16&17&18\\\hline ...players each. League rules state that a player must be paid at least <math>15,000</math> dollars, and that the total of all players' salaries for each te
  14 KB (2,199 words) - 13:43, 28 August 2020
• 2008 AMC 12B Problems/Problem 2
  15&16&17&18\\\hline 15&16&17&18\\\hline
  2 KB (219 words) - 23:53, 31 July 2023
• 2008 AMC 12B Problems/Problem 14
  {{AMC12 box|year=2008|ab=B|num-b=13|num-a=15}}
  806 bytes (126 words) - 10:54, 4 July 2013
• 2005 Alabama ARML TST Problems/Problem 14
  {{ARML box|year=2005|state=Alabama|num-b=13|num-a=15}}
  3 KB (478 words) - 23:41, 5 January 2014
• 2008 AIME I
  * [[2008 AIME I Problems/Problem 15]]
  1 KB (140 words) - 16:18, 17 October 2020
• 2008 AIME II
  * [[2008 AIME II Problems/Problem 15]]
  1 KB (140 words) - 16:18, 17 October 2020
• 2006 Alabama ARML TST
  ...to an easy [[AIME]], Alabaman scores average about 5 right, while the top 15 people usually answer 8 or more correctly. The first link contains the full * [[2006 Alabama ARML TST Problems/Problem 15]]
  1 KB (167 words) - 01:00, 19 June 2018
• 2006 Alabama ARML TST Problems
  \lfloor x \rfloor+\{y\} +z=15.3,\\ ==Problem 15==
  5 KB (769 words) - 20:56, 24 March 2015
• 2008 AMC 12B Problems/Problem 3
  ...players each. League rules state that a player must be paid at least <math>15,000</math> dollars, and that the total of all players' salaries for each te <math>700,000 = 20 * 15,000 + x</math>
  919 bytes (132 words) - 13:47, 15 February 2021
• 2008 AMC 12B Problems/Problem 9
  ...\ \frac {7}{2} \qquad \textbf{(C)}\ \sqrt {14} \qquad \textbf{(D)}\ \sqrt {15} \qquad \textbf{(E)}\ 4</math>
  2 KB (319 words) - 13:48, 15 February 2021
• 2008 AMC 12B Problems/Problem 25
  [ABCD]-([BCQ]+[APD]) &=\frac{15\cdot5\sqrt{3}}{2}-\frac{60\sqrt{3}}{8}\\ draw(rightanglemark(A,R,D,15));
  12 KB (2,015 words) - 20:54, 9 October 2022

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