2006 AMC 12A Problems/Problem 13

Problem

The vertices of a $3-4-5$ right triangle are the centers of three mutually externally tangent circles, as shown. What is the sum of the areas of the three circles?

$\mathrm{(A) \ } 12\pi\qquad \mathrm{(B) \ } \frac{25\pi}{2}\qquad \mathrm{(C) \ } 13\pi\qquad \mathrm{(D) \ } \frac{27\pi}{2}$ $\mathrm{(E) \ } 14\pi$

Solution

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$\rm{(E)}\,14\pi$

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2006 AMC 12A Problems/Problem 13

Problem

Solution

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