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2019 Mock AMC 10B Problems/Problem 2

Revision as of 10:43, 20 January 2020 by Vsamc (talk | contribs)

Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have ${6 \choose 3}=15$ \[\]$\boxed{\bold{C}}$ $\bold{15}$

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