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1953 AHSME Problems/Problem 37

Revision as of 20:39, 24 January 2020 by Rayfish (talk | contribs) (Created page with "==Problem== The base of an isosceles triangle is <math>6</math> inches and one of the equal sides is <math>12</math> inches. The radius of the circle through the vertices of...")
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Problem

The base of an isosceles triangle is $6$ inches and one of the equal sides is $12$ inches. The radius of the circle through the vertices of the triangle is:

$\textbf{(A)}\ \frac{7\sqrt{15}}{5} \qquad \textbf{(B)}\ 4\sqrt{3} \qquad \textbf{(C)}\ 3\sqrt{5} \qquad \textbf{(D)}\ 6\sqrt{3}\qquad \textbf{(E)}\ \text{none of these}$

Solution

See Also

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