2015 AMC 8 Problems/Problem 8

What is the smallest whole number larger than the perimeter of any triangle with a side of length $5$ and a side of length $19$ ?

$\textbf{(A) }24\qquad\textbf{(B) }29\qquad\textbf{(C) }43\qquad\textbf{(D) }48\qquad \textbf{(E) }57$

Solution

As per the tringle inequality, the sum of the length of any 2 sides is greater than the largest side. So, let $x$ be the third side and $19$ be the largest side. $5+x > 19$ . This gives the smallest value of $x$ as $15$ . The perimeter would be $5 + 15 + 19 = 39$ The smallest side which would be greater than the perimeter would be $\box{43}$ (Error compiling LaTeX. Unknown error_msg).

Page

Toolbox

Search

2015 AMC 8 Problems/Problem 8

Solution