1960 IMO Problems
Problems of the 2nd IMO 1960 Romania.
Contents
[hide]Day I
Problem 1
Problem 2
Problem 3
In a given right triangle , the hypotenuse , of length , is divided into equal parts ( and odd integer). Let be the acute angel subtending, from , that segment which contains the mdipoint of the hypotenuse. Let be the length of the altitude to the hypotenuse fo the triangle. Prove that: \[ \tan{\alpha}=\dfrac{4nh}{(n^2-1)a}. \]