1972 AHSME Problems/Problem 7
Revision as of 20:36, 28 January 2021 by Coolmath34 (talk | contribs) (Created page with "== Problem == If <math>yz:zx:xy=1:2:3</math>, then <math>\dfrac{x}{yz}:\dfrac{y}{zx}</math> is equal to <math>\textbf{(A) }3:2\qquad \textbf{(B) }1:2\qquad \textbf{(C) }1:...")
Problem
If 
, then 
is equal to
Solution
We want to find
![\[\dfrac{x}{yz}:\dfrac{y}{zx} = \dfrac{x}{yz} \cdot \dfrac{zx}{y} = \dfrac{x^2}{y^2}.\]](http://latex.artofproblemsolving.com/1/6/c/16c9ba987dcd86da704de478908806d211c450f8.png)
We are given 
and dividing both sides by 
gives 
Therefore,
![\[\dfrac{x^2}{y^2} = \dfrac{1}{\dfrac{1}{2^2}} = 4.\]](http://latex.artofproblemsolving.com/c/3/d/c3d43342437869ebd0c3e58fd91ec71f85693394.png)
The answer is 
-edited by coolmath34
