1963 TMTA High School Algebra I Contest Problem 4

Problem

The product of $3.5 \times 10^3$ and $1.8 \times 10^4$ is:

$\text{(A)} 5.3 \times 10^7 \quad \text{(B)} \quad 6.3 \times 10^7 \quad \text{(C)} \quad 6.3 \times 10^{12} \quad \text{(D)} \quad 5.3 \times 10^1 \quad \text{(E) NOTA}$

Solution

Multiply: $(3.5 \cdot 10^3)(1.8 \cdot 10^4) = (3.5 \cdot 1.8)(10^3 \cdot 10^4) = 6.3 \cdot 10^7$ The answer is $\boxed{\text{(B)}}.$

1963 TMTA High School Mathematics Contests (Problems)
Preceded by Problem 3	TMTA High School Mathematics Contest Past Problems/Solutions	Followed by Problem 5

Page

Toolbox

Search

1963 TMTA High School Algebra I Contest Problem 4

Problem

Solution

See Also