1955 AHSME Problems/Problem 39

Solution

The least possible value of $y$ is given at the $y$ coordinate of the vertex. The $x$ - coordinate is given by $\frac{-p}{2}$ . Plugging this into the quadratic, we get $y = \frac{p^2}{4} - \frac{p^2}{2} + q$ $0 = \frac{p^2}{4} - \frac{2p^2}{4} + q$ $$ (Error compiling LaTeX. Unknown error_msg)0 = \frac{-p^2}{4} + q$ $q = \frac{p^2}{4} = \boxed{B}$

~JustinLee2017

Page

Toolbox

Search

1955 AHSME Problems/Problem 39

Solution