1978 AHSME Problems/Problem 15
Revision as of 01:56, 13 February 2021 by Justinlee2017 (talk | contribs) (Created page with "==Solution== Squaring the equation, we get <cmath>\sin ^2 x + \cos ^2 x + 2 \sin x \cos x = \frac{1}{25} =\Rrightarrow 2\sin x \cos x = -\frac{24}{25} \Rrightarrow \sin x \cos...")
Solution
Squaring the equation, we get Recall that , so We can now solve for the values of and Since , we have
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