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2021 JMC 10 Problems/Problem 1

Revision as of 14:34, 1 April 2021 by Skyscraper (talk | contribs) (Created page with "== Problem == What is the value of <cmath>\dfrac{20}{2\cdot1} - \dfrac{2+0}{2/1}?</cmath> <math>\textbf{(A) } 3 \qquad\textbf{(B) } 7 \qquad\textbf{(C) } 8 \qquad\textbf{(D)...")
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Problem

What is the value of \[\dfrac{20}{2\cdot1} - \dfrac{2+0}{2/1}?\] $\textbf{(A) } 3 \qquad\textbf{(B) } 7 \qquad\textbf{(C) } 8 \qquad\textbf{(D) } 9 \qquad\textbf{(E) } 13$

Solution

We have $\frac{20}{2\cdot 1} - \frac{2+0}{2/1} = 10-1 = 9.$

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