If I have four boxes arranged in a $2 \times 2$ grid, in how many distinct ways can I place the digits $1$, $2$, and $3$ in the boxes, using each digit exactly once, such that each box contains at most one digit? (I only have one of each digit, so one box

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We can think of placing a $0$ in the fourth box that will necessarily be empty. Now the problem is simple: we have four choices of digits for the first box, three for the second, two for the third, and one for the last. Thus, there are $4\cdot 3\cdot 2\cdot 1 = \boxed{24}$ distinct ways to fill the boxes.