2002 OIM Problems/Problem 6

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Problem

Sequences $a_n$, and $b_n$ with $n \ge 0$ are defined by:

\[a_0=1 \text{, }b_0=4\text{, and}\]

\[a_{n+1}=a_n^{2001}+b_n\text{,  for }n \ge 0\text{.}\]

\[b_{n+1}=b_n^{2001}+a_n\text{,  for }n \ge 0\text{.}\]

Show that 2003 does not divide any of the terms of these sequences.

~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Solution

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See also

https://www.oma.org.ar/enunciados/ibe18.htm