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Solution to Principle of Insufficient Reason Introductory Problem 1

Revision as of 22:10, 19 January 2024 by Ddk001 (talk | contribs) (→‎Olympaid problem)
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Problem 1

$\text{Principle of Insufficient Reason} \implies \text{max} ([\text{hexagon}])=[\text{Regular Hexagon}]=\boxed{\frac{3}{2} \sqrt{3}}$

Olympaid problem

Principle of Insufficient Reason $\implies$ the max of $e$ is achieved when $a=b=c=d$ so \[4a+e=8\] \[4a^2+e^2=16\] \[\implies e=\frac{16}{5}\]

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