Proofs of AM-GM
This pages lists some proofs of the weighted AM-GM Inequality. The inequality's statement is as follows: for all nonnegative reals and nonnegative reals such that , then with equality if and only if for all such that .
We first note that we may disregard any for which , as they contribute to neither side of the desired inequality. We also note that if and , for some , then the right-hand side of the inequality is zero and the right hand of the inequality is greater or equal to zero, with equality if and only if whenever . Thus we may henceforth assume that all and are strictly positive.
Contents
Complete Proofs
Proof by Convexity
We note that the function is trictly concave. Then by Jensen's Inequality, with equality if and only if all the are equal. Since is a strictly increasing function, it then follows that with equality if and only if all the are equal, as desired.
Proofs of Unweighted AM-GM
These proofs use the assumption that , for all integers .
Proof by Rearrangement
Define the sequence as , for all integers . Evidently these sequences are similarly sorted. Then by the Rearrangement Inequality, where we take our indices modulo , with equality exactly when all the , and therefore all the , are equal. Dividing both sides by gives the desired inequality.