1970 AMC 12 Problems/Problem 2

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Problem

A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is

$\mathrm{(A) \ } pi/4\qquad \mathrm{(B) \ } 0\qquad \mathrm{(C) \ } h\qquad \mathrm{(D) \ } 2h$

$\mathrm{(E) \ }  h^3$

Solution