Mock AIME 1 2010 Problems/Problem 1

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Problem

Let $a_k = 7k + 4$. Find the number of perfect squares among $\{a_1, a_2, \ldots, a_{2010}\}$.

Solution

Since $n^2 = 7k+4$, $n^2$ is congruent to $4\pmod 7$. Taking the square root of both sides yields $n \equiv \pm 2 \pmod 7$. The maximum of $a_k$ is $14,074$, whose square root lies between $118$ and $119$. So, $n \leq 118$. The series of solutions for $n$ is $2, 9, 16...114$ and $5, 12, 19...117$. However, $2$ does not work because $2^2 = 4$, a value too small for $a_k$. Thus, there are $16 + 17 = \boxed{033}$ solutions.

See Also