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2024 AMC 12B Problems/Problem 15

Revision as of 00:59, 14 November 2024 by Mendenhallisbald (talk | contribs) (→‎Solution (Shoelace Theorem))

Solution (Shoelace Theorem)

We rewrite: $A(0,1)$ $B(\log _{2} 3, 2)$ $C(\log _{2} 7, 3)$.

From here we setup Shoelace Theorem and obtain: $\frac{1}{2}(2(\log _{2} 3) - log _{2} 7)$ Following log properties and simplifying gives (B).

~PeterDoesPhysics

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