2006 IMO Problems/Problem 3
Problem
Determine the least real number such that the inequality holds for all real numbers and .
Solution
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1. **Rewrite the expression:**
Consider the expression inside the absolute value:
By expanding and symmetrizing the terms, one can rewrite it as:
2. **Use a known factorization:**
A standard identity is:
Thus, our inequality becomes:
3. **Normalization:**
The inequality is homogeneous of degree 4. Without loss of generality, we may impose the normalization:
Under this constraint, we need to find the maximum possible value of:
4. **Finding the maximum:**
By considering an arithmetic progression substitution, for instance , and analyzing the resulting expression, it can be shown through careful algebraic manipulation and optimization that the maximum value under the unit norm constraint is:
5. **Conclusion:**
Since we have found the maximum value of the left-hand side expression (under normalization) to be , it follows that the minimal satisfying the original inequality is:
See Also
2006 IMO (Problems) • Resources | ||
Preceded by Problem 2 |
1 • 2 • 3 • 4 • 5 • 6 | Followed by Problem 4 |
All IMO Problems and Solutions |