Talk:2000 AIME I Problems/Problem 12
Revision as of 21:10, 28 March 2008 by Silversheep (talk | contribs) (New page: The explanation is unclear. I got the answer 352/2=176. From f(x)=f(x+352) all x with same residue mod 352 give the same answer. Additionally pairs (x,y) with x+y=46 mod 352 have same f(x)...)
The explanation is unclear. I got the answer 352/2=176. From f(x)=f(x+352) all x with same residue mod 352 give the same answer. Additionally pairs (x,y) with x+y=46 mod 352 have same f(x). There are 176 such pairs.
