1990 AJHSME Problems/Problem 16
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Problem
Solution
In the middle, we have .
If we match up the back with the front, and then do the same for the rest, we get pairs with and , so these will cancel out. In the middle, we have which doesn't cancel, but gives us .
See Also
1990 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 15 |
Followed by Problem 17 | |
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