KGS math club/solution 11 1
There are six ways:
- the vertices of a square
- the vertices of a 60-degree rhombus
- the vertices of an equlateral triangle, plus its midpoint
- the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away from the vertex through which that axis passes
- the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away, in the opposite direction, from the vertex through which that axis passes
- Four of the vertices of a regular pentagon