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1998 AHSME Problems/Problem 7

Revision as of 15:30, 6 June 2011 by BOGTRO (talk | contribs) (Created page with "== Problem 7 == If <math>N > 1</math>, then <math>\sqrt[3]{N\sqrt[3]{N\sqrt[3]{N}}} =</math> <math> \mathrm{(A) \ } N^{\frac 1{27}} \qquad \mathrm{(B) \ } N^{\frac 1{9}} \qquad ...")
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Problem 7

If $N > 1$, then $\sqrt[3]{N\sqrt[3]{N\sqrt[3]{N}}} =$

$\mathrm{(A) \ } N^{\frac 1{27}} \qquad \mathrm{(B) \ } N^{\frac 1{9}} \qquad \mathrm{(C) \ } N^{\frac 1{3}} \qquad \mathrm{(D) \ } N^{\frac {13}{27}} \qquad \mathrm{(E) \ } N$

Solution

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