AoPS Wiki talk:Problem of the Day/June 15, 2011

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Problem

AoPSWiki:Problem of the Day/June 15, 2011

Solution

We can solve this problem by a bit of trial and error. We can guess she rode $5$ days and we get $7+10+13+16+19=(13)(5)=65$ since the mean is clearly $13$ and there are $5$ terms. That's a bit too small. We can add $22$ to $65$ and get $87$. That's still to small. Now, we add $25$ to get $112$, the answer we want. We now count how many numbers are in the following list: $7, 10, 13, 16, 19, 22, 25$. Adding $2$ to the list gives us $9, 12, 15, 18, 21, 24, 27$. Dividing by $3$ gives us $3, 4, 5, 6, 7, 8, 9$. Subtracting $2$ gives us $1, 2, 3, 4, 5, 6, 7$. Our list has $7$ numbers. Since she started on a Monday, we must add $6$ days. Our answer is $\boxed{Sunday}$