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2002 AMC 8 Problems/Problem 3

Revision as of 12:07, 17 June 2011 by Hydroxide (talk | contribs) (Created page with "In order to get the smallest possible average, we want the 4 even numbers to be as small as possible. The first 4 positive even numbers are 2, 4, 6, and 8. Their average is <math...")
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In order to get the smallest possible average, we want the 4 even numbers to be as small as possible. The first 4 positive even numbers are 2, 4, 6, and 8. Their average is $\frac{2+4+6+8}{4}=\boxed{5}$.

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