AoPS Wiki talk:Problem of the Day/July 17, 2011

Revision as of 09:48, 17 July 2011 by Djmathman (talk | contribs) ({{potd_solution}} is not needed after you write a solution!)

Problem

AoPSWiki:Problem of the Day/July 17, 2011

Solution

By the Ptolemy's Theorem, we may say (MN x OP) + (NO x PM) = MO x NP. Substituting the values given, (3 x 5) + (4 x 3) = 6 x NP. 15 + 12 = 27 = 6NP. Thus, NP = 27/6 = 9/2.