AoPS Wiki talk:Problem of the Day/September 17, 2011
Revision as of 07:55, 17 September 2011 by Negativebplusorminus (talk | contribs) (Created page with "We know that <cmath>(999+1)^3=999^3+3(999)^2+3(999)+1</cmath> by the Binomial Theorem. Since our given expression is one less than that, we compute <cmath>(999+1)^3-1=1,000,000,...")
We know that by the Binomial Theorem. Since our given expression is one less than that, we compute