2004 AMC 8 Problems/Problem 3

Problem

Twelve friends met for dinner at Oscar's Overstuffed Oyster House, and each ordered one meal. The portions were so large, there was enough food for $18$ people. If they shared, how many meals should they have ordered to have just enough food for the $12$ of them?

$\textbf{(A)}\ 8\qquad\textbf{(B)}\ 9\qquad\textbf{(C)}\ 10\qquad\textbf{(D)}\ 15\qquad\textbf{(E)}\ 18$

Solution

Set up the proportion $\frac{12\text{meals}}{18\text{people}}=\frac{x\text{meals}}{12\text{people}}$ . Solving for $x$ gives us $x=8 \Rightarrow \boxed{\textbf{(A)}\ 8}$

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2004 AMC 8 Problems/Problem 3

Problem

Solution