2004 AMC 8 Problems/Problem 8

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Problem

Find the number of two-digit positive integers whose digits total $7$.

$\mathrm{(A)\ 6 }\qquad\mathrm{(B)\ 7 }\qquad\mathrm{(C)\ 8 }\qquad\mathrm{(D)\ 9 }\qquad\mathrm{(E)\ 10 }$

Solution

The numbers are $16, 25, 34, 43, 52, 61, 70$ which gives us a total of $7$. $\boxed{\textbf{(B)}\ 7}$