2013 AMC 12A Problems/Problem 1
Revision as of 20:50, 6 February 2013 by Indianninja707 (talk | contribs)
We are given that the area of ∆ABE is 40, and that side AB is of length 10.
Side AB can be used as the height of right ∆ABE.
Since A= (bh)/2,
40=(10h)/2
and solving for h will give us 8, or E.
