2013 AMC 12A Problems/Problem 11
Revision as of 23:55, 6 February 2013 by Indianninja707 (talk | contribs)
Let , and
. We want to find
, which is nothing but
.
Based on the fact that ,
, and
have the same perimeters, we can say the following:
Simplifying, we can find that
Since ,
.
After substitution, we find that , and
=
.
Again substituting, we find =
.
Therefore, =
, which is