1962 AHSME Problems/Problem 1

Revision as of 21:14, 9 November 2013 by Fadebekun (talk | contribs) (Created page with "The expression <math>\frac{1^{4y-1}}{5^{-1}+3^{-1}}</math> is equal to: <math>\textbf{(A)}\ \frac{4y-1}{8} \qquad</math> <math>\textbf{(B)}\ 8 \qquad</math> <math>\textbf{(C)}\...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

The expression $\frac{1^{4y-1}}{5^{-1}+3^{-1}}$ is equal to:

$\textbf{(A)}\ \frac{4y-1}{8} \qquad$ $\textbf{(B)}\ 8 \qquad$ $\textbf{(C)}\ \frac{15}{2} \qquad$ $\textbf{(D)}\ \frac{15}{8} \qquad$ $\textbf{(E)}\ \frac{1}{8} \qquad$