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1964 AHSME Problems/Problem 38

Revision as of 17:22, 5 March 2014 by Bobthesmartypants (talk | contribs) (Created page with "==Problem== The sides <math>PQ</math> and <math>PR</math> of triangle <math>PQR</math> are respectively of lengths <math>4</math> inches, and <math>7</math> inches. The median <...")
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Problem

The sides $PQ$ and $PR$ of triangle $PQR$ are respectively of lengths $4$ inches, and $7$ inches. The median $PM$ is $3\frac{1}{2}$ inches. Then $QR$, in inches, is:

$\textbf{(A) }6\qquad\textbf{(B) }7\qquad\textbf{(C) }8\qquad\textbf{(D) }9\qquad \textbf{(E) }10$

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