2013 USAJMO Problems/Problem 6

Revision as of 09:56, 14 April 2014 by Suli (talk | contribs) (Solution)

Solution

Without loss of generality, let $x \le y \le z$. Then $\sqrt{x + xyz} = \sqrt{x - 1} + \sqrt{y - 1} + \sqrt{z - 1}$.