1969 AHSME Problems/Problem 6

Problem

The area of the ring between two concentric circles is $12\tfrac{1}{2}\pi$ square inches. The length of a chord of the larger circle tangent to the smaller circle, in inches, is:

$\text{(A) } \frac{5}{\sqrt{2}}\quad \text{(B) } 5\quad \text{(C) } 5\sqrt{2}\quad \text{(D) } 10\quad \text{(E) } 10\sqrt{2}$

Solution

$\fbox{C}$

1969 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 5	Followed by Problem 7
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1969 AHSME Problems/Problem 6

Problem

Solution

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