2017 AIME II Problems/Problem 8
Revision as of 11:36, 23 March 2017 by The turtle (talk | contribs) (Created page with "<math>\textbf{Problem 8}</math> Find the number of positive integers <math>n</math> less than <math>2017</math> such that <cmath>1+n+\frac{n^2}{2!}+\frac{n^3}{3!}+\frac{n^4}{4...")
Find the number of positive integers 
less than 
such that ![\[1+n+\frac{n^2}{2!}+\frac{n^3}{3!}+\frac{n^4}{4!}+\frac{n^5}{5!}+\frac{n^6}{6!}\]](http://latex.artofproblemsolving.com/f/2/d/f2d4dca8ba4d995abb248a3376422194050e1649.png)
is an integer.
