2018 AMC 10A Problems/Problem 18
How many nonnegative integers can be written in the form
where
for
?
Solution
This looks like balanced ternary, in which all the integers with absolute values less than are represented in
digits. There are 8 digits. Plugging in 8 into the formula gives a maximum bound of
, which means there are 3280 positive integers, 0, and 3280 negative integers. Since we want all nonnegative integers, there are
integers or
.