2002 AMC 8 Problems/Problem 13

Revision as of 19:57, 20 March 2018 by Proximacentauri (talk | contribs) (Solution)

Problem

For his birthday, Bert gets a box that holds 125 jellybeans when filled to capacity. A few weeks later, Carrie gets a larger box full of jellybeans. Her box is twice as high, twice as wide and twice as long as Bert's. Approximately, how many jellybeans did Carrie get?

$\text{(A)}\ 250\qquad\text{(B)}\ 500\qquad\text{(C)}\ 625\qquad\text{(D)}\ 750\qquad\text{(E)}\ 1000$

Solution

Since the volume ratio is equal to the sides ratio cubed, then the ratio of the larger boxe's volume to the smaller one is 2 cubed.

$2^3=8$ Now multiply 125 (the number of jellybeans that Bert's box can hold) by 8. $8*125= \boxed{\text{(E)}\ 1000}$.

See Also

2002 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
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All AJHSME/AMC 8 Problems and Solutions

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