Difference between revisions of "1951 AHSME Problems/Problem 19"

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== Solution ==  
 
== Solution ==  
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We can express any of these types of numbers in the form <math>\overline{abc}\times 1001</math>, where <math>\overline{abc}</math> is a 3-digit number. Therefore, the answer is <math>\textbf{(E)}\ 1001</math>
  
 
== See Also ==
 
== See Also ==

Revision as of 21:22, 10 April 2013

Problem

A six place number is formed by repeating a three place number; for example, $256256$ or $678678$, etc. Any number of this form is always exactly divisible by:

$\textbf{(A)}\ 7 \text{ only} \qquad\textbf{(B)}\ 11 \text{ only} \qquad\textbf{(C)}\ 13 \text{ only} \qquad\textbf{(D)}\ 101 \qquad\textbf{(E)}\ 1001$

Solution

We can express any of these types of numbers in the form $\overline{abc}\times 1001$, where $\overline{abc}$ is a 3-digit number. Therefore, the answer is $\textbf{(E)}\ 1001$

See Also

1951 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 18
Followed by
Problem 20
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All AHSME Problems and Solutions