# Difference between revisions of "1953 AHSME Problems/Problem 2"

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− | The first discount takes off <math>20\%</math> of the price, so the cost of the refrigerator is <math>0.8\cdot250</math>. The next discount takes off <math>15\%</math>, so the cost of the refrigerator is now <math>0. | + | The first discount takes off <math>20\%</math> of the price, so the cost of the refrigerator is <math>0.8\cdot250</math>. The next discount takes off <math>15\%</math>, so the cost of the refrigerator is now <math>0.8\cdot0.85\cdot250=0.68\cdot250</math>. Thus, the sale price of the refrigerator is <math>\boxed{\textbf{(D)} \text{68\% of 250.00}}</math>. |

## Revision as of 20:14, 1 April 2017

## Problem

A refrigerator is offered at sale at $250.00 less successive discounts of 20% and 15%. The sale price of the refrigerator is:

## Solution

The first discount takes off of the price, so the cost of the refrigerator is . The next discount takes off , so the cost of the refrigerator is now . Thus, the sale price of the refrigerator is .