Difference between revisions of "1953 AHSME Problems/Problem 6"
Katzrockso (talk | contribs) (Created page with "==Problem 6== Charles has <math>5q + 1</math> quarters and Richard has <math>q + 5</math> quarters. The difference in their money in dimes is: <math>\textbf{(A)}\ 10(q - 1)...") |
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Revision as of 11:57, 7 June 2016
Problem 6
Charles has quarters and Richard has quarters. The difference in their money in dimes is:
Solution
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