Difference between revisions of "1954 AHSME Problems/Problem 4"
Katzrockso (talk | contribs) (Created page with "== Problem 4== If the Highest Common Divisor of <math>6432</math> and <math>132</math> is diminished by <math>8</math>, it will equal: <math>\textbf{(A)}\ -6 \qquad \textbf...") |
(No difference)
|
Revision as of 13:37, 6 June 2016
Problem 4
If the Highest Common Divisor of and is diminished by , it will equal:
Solution
, so $\gcd(2^5\cdot 3\cdot 67, 2^2\cdot 3\cdog 13)=2^2\cdot 3=12\implies 12-8=4, \fbox{E}$ (Error compiling LaTeX. Unknown error_msg)