1955 AHSME Problems/Problem 16

Problem 16

The value of $\frac{3}{a+b}$ when $a=4$ and $b=-4$ is:

$\textbf{(A)}\ 3\qquad\textbf{(B)}\ \frac{3}{8}\qquad\textbf{(C)}\ 0\qquad\textbf{(D)}\ \text{any finite number}\qquad\textbf{(E)}\ \text{meaningless}$

Solution

As the denominator is $4 - (-4) = 0$ , the value of the fraction $\frac{3}{4 - (-4)}$ is $\textbf{(E)}\ \text{meaningless}$

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1955 AHSME Problems/Problem 16

Problem 16

Solution