Difference between revisions of "1955 AHSME Problems/Problem 6"

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Revision as of 11:17, 28 April 2019

Since we are buying at $3$ for $10$ cents and $5$ for $20$ cents, let's assume that together, we are buying 15 oranges. That means that we are getting a total of $30$ oranges for $(10*5) + (20*3)$ cents. That comes to a total of $30$ oranges for $110$ cents. $110/30$ = $11/3$ and we are done. -Brudder