Revision history of "1956 AHSME Problems/Problem 18"

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  • (cur | prev) 18:40, 12 February 2021Coolmath34 (talk | contribs). . (531 bytes) (+531). . (Created page with "== Problem == If <math>10^{2y} = 25</math>, then <math>10^{ - y}</math> equals: <math> \textbf{(A)}\ -\frac{1}{5}\qquad \textbf{(B)}\ \frac{1}{625}\qquad \textbf{(C)}\ \fr...")